Precalculus. Solve for z log of z-3=2. log(z āˆ’ 3) = 2 log ( z - 3) = 2. Rewrite log(zāˆ’ 3) = 2 log ( z - 3) = 2 in exponential form using the definition of a logarithm. If x x and b b are positive real numbers and b ≠ 1 b ≠ 1, then logb(x) = y log b ( x) = y is equivalent to by = x b y = x. 102 = zāˆ’3 10 2 = z - 3. .
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